Determining Quadrants in a Matrix

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TS
TS 2015-5-4
评论： Yong Cho 2019-10-1
matrix=load('Data');
x=matrix(:,1);
y=matrix(:,2);
if x>0 & y>0
matrix(:,3)=1
elseif x<0 & y>0
matrix(:,3)=2
elseif x<0 & y<0
matrix(:,3)=3
elseif x>0 & y<0
matrix(:,3)=4
elseif x<-128 & y<-128 & x>128 & y>128
'Invalid Values'
end
With this code, I'm trying to put separate points into a matrix. However, my code doesn't do anything with the values as far as I have seen. I was trying to put the quadrant values into a third column so that I could code the script to count all points in each quadrant, so there is a reason for it. If you have any suggestions I would greatly appreciate it.

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采纳的回答

Jan
Jan 2015-5-4
The if command evaluates the condition as a scalar. This is logical, because what could this mean:
if [true, false]
? Is this true or not? Therefore Matlab inserts a all() in the condition, if the user forgot this. So you have:
if all(x>0 & y>0)
And this is never true. What you want is:
index = (x>0 & y>0);
matrix(index, 3) = 1;
...
The last condition is magic:
elseif x<-128 & y<-128 & x>128 & y>128
You are looking for numbers which are smaller than -128 and larger than 128? You want an or.

更多回答（1 个）

Stephen23
Stephen23 2015-5-4
编辑：Stephen23 2015-5-4
Actually you do not need these if statements at all: just use logical indexing directly, like this:
matrix = load('Data');
x = matrix(:,1);
y = matrix(:,2);
matrix(x>0 & y>0,3) = 1;
matrix(x<0 & y>0,3) = 2;
matrix(x<0 & y<0,3) = 3;
matrix(x>0 & y<0,3) = 4;

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