Why converting from Spherical to Cartesian using the command "sph2cart" gives different values than converting it manually by writing the equations of each coordinate?

7 次查看（过去 30 天）
Reem
Reem 2024-9-7
回答： Voss 2024-9-7

请先登录，再回答此问题。

采纳的回答

Voss
Voss 2024-9-7
Ran in:
Assuming theta is azimuth and phi is elevation, your equations would be (from the documentation):
x = r .* cos(phi) .* cos(theta)
y = r .* cos(phi) .* sin(theta)
z = r .* sin(phi)
Making those corrections gives:
r = 10;
theta = pi/4;
phi = pi/3;
x = r*cos(phi)*cos(theta)
x = 3.5355
y = r*cos(phi)*sin(theta)
y = 3.5355
z = r*sin(phi)
z = 8.6603
And note that the order of the inputs to sph2cart is azimuth before elevation:
[x,y,z] = sph2cart(theta,phi,r)
x = 3.5355
y = 3.5355
z = 8.6603

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Dates and Time 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by