It took a few seconds staring at the output you expect to see, and realize what you meant. I THINK the first element in each row of that output gives you the number in question, and then the rest of the elements in that row are the respective lengths of the corresponding subsequences.
Nothing stops you from using a loop however! First, find the set of elements you need to consider. unique gives you that simply enough.
V = [1 1 1 3 3 1 1 4 4 4 4 1 1 3 3 3 2 2 2 2];
uniqueV = unique(V)
Next, you can simply loop over the elements of uniqueV. For example, when V == 1, where does each segment start and end? You can use tools like strfind to locate those indices.
C = cell(numel(uniqueV),1);
for ind = 1:numel(uniqueV)
vloc = V == uniqueV(ind);
substrlengths = strfind([vloc,0],[1 0]) - strfind([0,vloc],[0 1]) + 1;
C{ind} = {uniqueV(ind),substrlengths};
end
C
And that is effectively what you want. I chose to use a cell array to store the result, where each cell is split into another cell array.
C{:}
You could have done differently. A struct might also be a good way to store the data.
