Looping string array into parsed timestamp
1 次查看(过去 30 天)
显示 更早的评论
I have the following data that I would like to parse into hours:minutes:secs to plot against other data.
Here is my code that is causing issues with the indexing.
TS = ["085423","085428","085431","085502"];
TS = TS';
for i = 1:length(TS)
timestr = TS(i);
end
hours = timestr(1:2);
minutes = timestr(3:4);
secs = timestr(5:6);
formatted_time_str = [hours, ':', minutes, ':', secs];
Any insight is appreciated. Thank you.
0 个评论
采纳的回答
Stephen23
2024-9-17
编辑:Stephen23
2024-9-17
"... that is causing issues with the indexing."
Because you are mixing up indexing into string arrays with the characters contained within them. Not the same things at all: indexing into a string array indexes into the string array, not into the characters it contains (as you incorrectly assumed).
TS = ["085423","085428","085431","085502"]
Method one: returns a string array:
FS = extractBefore(TS(:),3)+":"+extractBetween(TS(:),3,4)+":"+extractAfter(TS(:),4)
Method two: returns a char matrix:
FS = repmat(':',numel(TS),8);
FS(:,[1:2,4:5,7:8]) = char(TS(:))
5 个评论
Stephen23
2024-9-18
"In trying to plot the FS data (timestamp) against numerical data I get an error message:"
If you are trying to plot with this data, then you are likely much better of using DURATION objects rather than fiddling around with text or numerics:
TS = ["085423";"085428";"085431";"085502"];
H = str2double(extractBefore(TS(:),3));
M = str2double(extractBetween(TS(:),3,4));
S = str2double(extractAfter(TS(:),4));
D = duration(H,M,S)
Y = rand(size(D));
scatter(D,Y)
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Characters and Strings 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!