Replace the element in the cell array with space inbetween
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I have a cell array element = {'num riqu' ; 'num riqu' ; 'con tant' ; 'con tant'}
I need to replace num riqu = numeric
con tant = constant
how can I do this ?
采纳的回答
Guillaume
2015-5-6
It's not clear how generic of an answer you are looking for. In you particular example, the simplest way would be:
c = {'num riqu' ; 'num riqu' ; 'con tant' ; 'con tant'};
c(strcmp(c, 'num riqu')) = {'numeric'};
c(strcmp(c, 'con tant')) = {'constant'}
3 个评论
Guillaume
2015-5-6
A more generic way:
c = {'num riqu' ; 'num riqu' ; 'con tant' ; 'con tant'};
replacements = {'num riqu', 'numeric'
'con tant', 'constant'};
%column 1 of replacements is word to replace, column 2 is replacement
[toreplace, replacementrow] = ismember(c, replacements(:, 1));
c(toreplace) = replacements(replacementrow, 2)
Gopalakrishnan venkatesan
2015-5-6
编辑：Gopalakrishnan venkatesan
2015-5-6
Guillaume
2015-5-6
You would have to use one regexprep per expression you want to replace, so while you could do it, it wouldn't be any simpler.
In any case, as defined in your example, the search patterns don't need regular expressions.
更多回答（1 个）
Azzi Abdelmalek
2015-5-6
element = {'num riqu' ; 'num riqu' ; 'con tant' ; 'con tant'}
element=strrep(element,'num riqu','numeric');
element=strrep(element,'con tant','constant')
2 个评论
Gopalakrishnan venkatesan
2015-5-6
编辑：Gopalakrishnan venkatesan
2015-5-6
Azzi Abdelmalek
2015-5-6
element = {'num riqu' ; 'num riqu' ; 'con tant' ; 'con tant'}
element=regexprep(element,'num riqu','numeric')
element=regexprep(element,'con tant','constant')
But strrep is faster then regexprep
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