Replace the element in the cell array with space inbetween

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Gopalakrishnan venkatesan
评论： Azzi Abdelmalek 2015-5-6
I have a cell array element = {'num riqu' ; 'num riqu' ; 'con tant' ; 'con tant'}
I need to replace num riqu = numeric
con tant = constant
how can I do this ?

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采纳的回答

Guillaume
Guillaume 2015-5-6
It's not clear how generic of an answer you are looking for. In you particular example, the simplest way would be:
c = {'num riqu' ; 'num riqu' ; 'con tant' ; 'con tant'};
c(strcmp(c, 'num riqu')) = {'numeric'};
c(strcmp(c, 'con tant')) = {'constant'}
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Guillaume
Guillaume 2015-5-6
You would have to use one regexprep per expression you want to replace, so while you could do it, it wouldn't be any simpler.
In any case, as defined in your example, the search patterns don't need regular expressions.

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更多回答（1 个）

Azzi Abdelmalek
Azzi Abdelmalek 2015-5-6
element = {'num riqu' ; 'num riqu' ; 'con tant' ; 'con tant'}
element=strrep(element,'num riqu','numeric');
element=strrep(element,'con tant','constant')
  2 个评论
Azzi Abdelmalek
Azzi Abdelmalek 2015-5-6
element = {'num riqu' ; 'num riqu' ; 'con tant' ; 'con tant'}
element=regexprep(element,'num riqu','numeric')
element=regexprep(element,'con tant','constant')
But strrep is faster then regexprep

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