question about symmetric in function: rlgc2s

1 次查看(过去 30 天)
I found there is a symmetrize at the end of matlab funciton:rlgc2s, code as below.
s_params(1:num lines1:num lines,m) = 0.5*(S11 + S11.');
I wonder the physical meaning of this option?
For a symmertric differential transmission, this option will make S12 = S21, but it missed S11 = S22.
For a symmertric transmission with 3 lines, this option will make S12 = S21, but I think S12 should equals S32 rather than S21.

回答(1 个)

Vinay
Vinay 2024-9-23
Hi Kuan,
The symmetrize is used at the end of the function to ensure the individual s parameter of the network are symmetric.
For a 2 – port symmetric reciprocal network, the conditions s12 = s21 and s11 = s22 holds
This is due to the reciprocal nature of the network, which ensures that the ABCD parameters satisfy
(AD - BC = 1), leading to ( s12 = s21). The symmetric network condition requires (A = D ) in the ABCD parameters, which makes the numerators of s11 and s22 identical, as defined below:
s11 = (A + B./z0 - C.*z0 - D)/den
s22 = (-A + B./z0 - C.*z0 + D)/den
This ensures the s11 = s22 and s21= s12 for a 2-port network.
In case of 3 transmission line the reciprocal network ensures sij = sji so s21 = s12 follows. However, the parameters s12 and s32 are independent and do not necessarily equal each other.
Kindly refer to the below documentation of “rlgc2s” for more details:
I hope this helps!

类别

Help CenterFile Exchange 中查找有关 Programming 的更多信息

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by