Choose role of NaN when summing two matrices

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Roderick
Roderick 2024-9-28
回答： Voss 2024-9-28
Dear all
Some time ago, I posted this question: Choosing the role of NaN elements in the sum environment of matrices. That worked great when doing the mean value, but now imagine that I just want to sum the two matrices, given by:
aa=[1 2; 3 NaN];
bb=[NaN 1; 2 NaN];
so that I obtain:
cc=[1 3; 5 NaN];
If I do something like:
cc=sum(cat(3,aa,bb),3,'omitnan')
that gives:
cc=[1 3; 5 0];
Which way would be the best in this case?

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Voss
Voss 2024-9-28
Ran in:
Here's one way:
aa=[1 2; 3 NaN];
bb=[NaN 1; 2 NaN];
tmp = cat(3,aa,bb);
cc=sum(tmp,3,'omitnan');
cc(all(isnan(tmp),3)) = NaN
cc = 2×2
1 3 5 NaN
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