How do I solve this differential equation?
显示 更早的评论
Hi,
for a Project I have to solve the following differential equation:
y''=-((m*B0)/I)*sin(y)
m, B0 and I are numerical values
I already tried the following but it won't work.
B0=0.0354;
m=7.6563e-5;
I=1.2272e-14;
tspan=[0, 0.0001];
y0=0.139626;
[t,y] = ode45(@(t,y) odefcn(t,y), tspan, y0);
function dydt=odefcn(y,m,B0,I)
dydt=y;
dydt(1)=-(m*B0)/I*sin(y);
end
Thanks in advance!
采纳的回答
Put the constants inside the function.
tspan = [0, 1e-3];
y0 = [0.139626; 0];
[t, y] = ode45(@(t,y) odefcn(t,y), tspan, y0);
plot(t, y), grid on
function dydt=odefcn(t, y)
B0 = 0.0354;
m = 7.6563e-5;
I = 1.2272e-14;
dydt = zeros(2, 1);
dydt(1) = y(2);
dydt(2) = -(m*B0)/I*sin(y(1));
end
1 个评论
Or, just use a function handle. The function handle grabs whatever values of those constants from the caller workspace it needs, then stores them in the workspace of the function handle. So you need not write an m-file function, and you can pass around the function handle now, where it will always know those values.
B0 = 0.0354;
m = 7.6563e-5;
I = 1.2272e-14;
dydt = @(t,y) [y(2) ; -(m*B0)/I*sin(y(1))];
tspan = [0, 1e-3];
y0 = [0.139626; 0];
[t, y] = ode45(dydt, tspan, y0);
plot(t, y), grid on
Just be careful, as if you then later on change the values of B0. m, or I, the change will not be reflected in the function handle workspace. It will still remember the original values.
So alternatively, if you wanted to pass in those values to the function handle, you could do this:
dydt = @(t,y,B0,m,I) [y(2) ; -(m*B0)/I*sin(y(1))];
tspan = [0, 1e-3];
y0 = [0.139626; 0];
[t, y] = ode45(@(t,y) dydt(t,y,B0,m,I), tspan, y0);
plot(t, y), grid on
As you can see, the parameters B0, m, and i are all being passed into dydt, because I created a new function handle on the fly in the call to ode45. Now if you wanted to change those values later on, it is easier to do.
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