Why I am getting error while using qammod function ?

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majdi Khlfalla
majdi Khlfalla 2024-10-25
编辑： majdi Khlfalla 2024-10-26
Ran in:
Hi
I am using matlab R2014a and I using the code below :
%% Simulation Parameters
numBits = 20000;
modOrder = 16;
%% Creat a source signal and apply 16-QAM modulation
srcBits = randi([0 1],numBits,1);
modOut = qammod(srcBits,modOrder,'InputType','Bit','UnitAveragePower',true);
%% Apply AWGN
SNR = 15;
chanOut = awgn(modOut,SNR);
scatterplot(chanOut)
%% Demodulate received signal
demodOut = qamdemod(chanOut,modOrder,'OutputType','Bit','UnitAveragePower',true);
I should have got the figuer above. But I am having the following error instead !
( Note : I run this code while typing my question and got the result above )
Error using qammod (line 28)
Too many input arguments.
and line 28 is found here :
27 - if(nargin>4)
28 - error(message('comm:qammod:numarg2'));
29 - end
thank you
  2 个评论
Walter Roberson
Walter Roberson 2024-10-25
You should double-check your help documentation.
I suspect that back in R2014a that there was no support for 'UnitAveragePower'
majdi Khlfalla
majdi Khlfalla 2024-10-26
编辑：majdi Khlfalla 2024-10-26
@Walter Roberson yes, I did some research and found that problem was my matlab version. And instead of averaging power, I have to noramlize it in separate step. Thank you walter for your help

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采纳的回答

Saurabh
Saurabh 2024-10-25
Hi @majdi Khlfalla,
I've encountered a similar issue in the past, and I was able to resolve it by upgrading my MATLAB version to R2016a or later.
I Hope this helps

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