VPA behavior, workaround requested
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Does anybody now a workaround for this behaviour of vpa?:
syms a b c
c=a+b; a=1; b=1;
vpa(c)
ans =
a + b
while
vpa(a+b)
returns the expected ans=2. I know I could define c after a and b, but in my particular program (the above is just a minimal example), this is not possible. So I am looking for a simple workaround (vpa(char(c)) also does not work).
采纳的回答
Star Strider
2015-5-14
Use the subs function inside the vpa call:
syms a b c
c=a+b; a=1; b=1;
vpa(subs(c))
produces:
ans =
2.0
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