Array indices must be positive integers or logical values.

2024 11 25
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更新时间：2024 11 25
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Hi i have define the function
function y=triangle_basisn(phi,kk)
%[f,N,ra,k0,Z0,lambda] = parameter();
N=40
dftm=2.*pi./(N-1);
for jj = 1:N
Phi0(jj)=(jj-1).*dftm;
end
Phin=Phi0;
if ( phi >= Phin(kk-1) ) & ( phi <=Phin(kk))
y=(phi-Phin(kk-1))./dftm
elseif (phi >= Phin(kk) ) & (phi <=Phin(kk+1))
y=(Phin(kk+1)-phi)./dftm
else
y=0
end
end
When i call the funcrion i receive the message
Array indices must be positive integers or logical values.
i thni the problem is the tem kk-1 when kk=1 the matlab cant define zero index ?
there a way to ovecomne the problem ?
thank
George

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Cris LaPierre
Cris LaPierre 2024-11-25
编辑：Cris LaPierre 2024-11-25
Ran in:

0 个投票

Ran in:
I can reproduce the error if I set kk=1. In this case, Phin(kk-1) becomes Phin(0), which is causing the error. In MATLAB, the index cannot be 0.
y=triangle_basisn(10,1)
N = 40
Array indices must be positive integers or logical values.

Error in solution>triangle_basisn (line 11)
if ( phi >= Phin(kk-1) ) & ( phi <=Phin(kk))
function y=triangle_basisn(phi,kk)
%[f,N,ra,k0,Z0,lambda] = parameter();
N=40
dftm=2.*pi./(N-1);
for jj = 1:N
Phi0(jj)=(jj-1).*dftm;
end
Phin=Phi0;
if ( phi >= Phin(kk-1) ) & ( phi <=Phin(kk))
y=(phi-Phin(kk-1))./dftm
elseif (phi >= Phin(kk) ) & (phi <=Phin(kk+1))
y=(Phin(kk+1)-phi)./dftm
else
y=0
end
end
One way to overcome this is to define an if condition for when kk=1. What the corresponding code does would be up to you, but it would prevent the error. Here's an example:
if kk==1
y=phi;
elseif( phi >= Phin(kk-1) ) & ( phi <=Phin(kk))
y=(phi-Phin(kk-1))./dftm
elseif (phi >= Phin(kk) ) & (phi <=Phin(kk+1))
y=(Phin(kk+1)-phi)./dftm
else
y=0
end

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