the array index is not matching

52 次查看（过去 30 天）
yogeshwari patel
yogeshwari patel 2024-11-28，3:45
评论： yogeshwari patel 2024-12-2，5:02
syms x mu gamma
syms t %c
alpha=1
U=zeros(1,2,'sym')
V=zeros(1,2,'sym');
A=zeros(1,1,'sym');
B=zeros(1,1,'sym');
C=zeros(1,1,'sym');
D=zeros(1,1,'sym');
series1(x,t)=sym(zeros(1,1));
series2(x,t)=sym(zeros(1,1));
%%%%%%%%%%%%%%%%%%%%% initial condition
%mu=1
U(1)=mu*exp(1i*x)
V(1)=gamma*exp(1i*x)
u=conj(U(1))
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
for m=1
A(1)=0;
B(1)=0;
for j=1:m
for k=1:j
A(1)=A(1)+U(k)*V(j-k+1)*conj(V(m-j+1));
B(1)=B(1)+V(k)*U(j-k+1)*conj(U(m-j+1));
end
end
U(m+1)=gamma(((m-1)*alpha)+1)/gamma((alpha*(m+1-1))+1)*1i*(1i*diff(U(m),x,1)+V(m)+A(1))
V(m+1)=gamma(((m-1)*alpha)+1)/gamma((alpha*(m+1-1))+1)*(-1i*diff(V(m),x,1)+U(m)+B(1))
end
Index exceeds the number of array elements. Index must not exceed 1.
Error in indexing (line 936)
R_tilde = builtin('subsref',L_tilde,Idx);
why it showing the error ? As I will compute diff(U(m),x,1)+V(m)+A(1)) . The index in each term will be 1 .

请先登录，再回答此问题。

采纳的回答

Vinay
Vinay 2024-11-28，4:19
Hi @yogeshwari patel,
The issue is due to the 'gamma' variable which is being used both as a symbolic variable and as a function in the below code
U(m+1)=gamma(((m-1)*alpha)+1)/gamma((alpha*(m+1-1))+1)*1i*(1i*diff(U(m),x,1)+V(m)+A(1))
V(m+1)=gamma(((m-1)*alpha)+1)/gamma((alpha*(m+1-1))+1)*(-1i*diff(V(m),x,1)+U(m)+B(1))
The above code treats 'gamma' as a function and causing the error.The workaround is to use the multiplication operator after the variable 'gamma' in the expression
U(m+1)=gamma*(((m-1)*alpha)+1)/gamma*((alpha*(m+1-1))+1)*1i*(1i*diff(U(m),x,1)+V(m)+A(1))
V(m+1)=gamma*(((m-1)*alpha)+1)/gamma*((alpha*(m+1-1))+1)*(-1i*diff(V(m),x,1)+U(m)+B(1))
I hope this helps!

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Data Distribution Plots 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by