Converting product into individual entries

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Mahendra Yadav
Mahendra Yadav 2025-1-20
评论： Mahendra Yadav 2025-1-21
Can I write [4*3 5 7*0 11 3*9] in the following format.
[3,3,3,3,5,0,0,0,0,0,0,0,11,9,9,9]
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Mahendra Yadav
Mahendra Yadav 2025-1-20
For any product, Let's say we have a*b.
Then "a" refers here to the number of times, the value "b" should appear.
Hence for a*b, we have
[b,b,b,b,b,b.....(a times)]
Stephen23
Stephen23 2025-1-20
@Mahendra Yadav: Sure, I know what product is. But nowhere do you explain how were are supposed to determine which factors you want to use. For example, given the product 12 you could have:
  • a=3 b=4
  • a=4 b=3
  • a=2 b=6
  • a=6 b=2
  • a=1 b=12
  • a=12 b=1
So far you have given absolutely no explanation of how you want to select the specific factors given some random value.
Or perhaps you are just not explaining the form that your data actually have. I cannot guess this.

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采纳的回答

Steven Lord
Steven Lord 2025-1-20
If you have the individual terms and their replication factors already, see the repelem function. If you don't you may need to use the factor function first.
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Mahendra Yadav
Mahendra Yadav 2025-1-20
Yes, I'm aware about both of these functions. But how can I implement these in the above mentioned array.
Or
wheter any alternative solutions are possible?
Steven Lord
Steven Lord 2025-1-20
Ran in:
Do you have your data in this form?
option1 = [4*3 5 7*0 11 3*9]
option1 = 1×5
12 5 0 11 27
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Or do you have data in this form?
option2a = [4 1 7 1 3]
option2a = 1×5
4 1 7 1 3
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option2b = [3 5 0 11 9]
option2b = 1×5
3 5 0 11 9
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If you have option 1, how do you handle the ambiguity with 7*0 called out by Stephen23?
And since you seem to be trying to do something with prime factorizations, why is the first group [3 3 3 3] and not [2 2 2 2 2 2] (which you would write 6*2)? Both those groups sum to 12 which is the first element of option1, so how do you disambiguate? And why isn't the third group just empty [] (zero 7s) instead of [0 0 0 0 0 0 0] (seven 0s)?
With option 2:
x = repelem(option2b, option2a)
x = 1×16
3 3 3 3 5 0 0 0 0 0 0 0 11 9 9 9
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更多回答（1 个）

Xiaotao
Xiaotao 2025-1-20
Ran in:
a = [3*ones(1,4), 5, zeros(1,7), 11, 9*ones(1,3)]
a = 1×16
3 3 3 3 5 0 0 0 0 0 0 0 11 9 9 9
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Stephen23
Stephen23 2025-1-21
Ran in:
The simpler MATLAB approach:
cnt = [4,1,7,1,3]; % counts
val = [3,5,0,11,9]; % values
out = repelem(val,cnt)
out = 1×16
3 3 3 3 5 0 0 0 0 0 0 0 11 9 9 9
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