Find items of a matrix using a per-column index

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SHC
SHC 2025-1-27
回答： Anton Kogios 2025-1-27
If
A = [1, 2, 3;
4, 5, 6]
and I have a per-column index.
idx = [2, 2, 1]
I want to find the items of A with the per-column index.
So the result I want is:
[4, 5, 3]
I know this can be done with a for loop, however, is there a way to do this without using loops?

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采纳的回答

Anton Kogios
Anton Kogios 2025-1-27
Ran in:
A = [1, 2, 3; 4, 5, 6];
idx = [2, 2, 1];
linearIndices = sub2ind(size(A), idx, 1:length(idx));
result = A(linearIndices)
result = 1×3
4 5 3
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