Why does containers.Map('KeyType','double') silently return a map with KeyType 'char' ?
显示 更早的评论
I would have expected an error if the second argument is strictly required. Giving me a wrong map just pushes the error to runtime when I call it with an 'double' key. No idea what went into this design.
采纳的回答
containers.Map('KeyType','double')
is interpreted as being an instance of calling
M = containers.Map(keySet,valueSet)
You need to provide the 'ValueType' on the same call in order for it to be interpreted as keytype
c = containers.Map('KeyType','double','ValueType','double')
3 个评论
Vijay
2025-2-1
Vijay
2025-2-1
If we allowed users to specify just the KeyType or just the ValueType, the call you wrote would be ambiguous. Do you intend to set just the type and populate the containers.Map object with no data, or did you intend to create a containers.Map object with just one piece of data, where the key just happened to be either 'KeyType' or 'ValueType'?
With the design as implemented, there's no ambiguity. With two inputs you're specifying a key and value pair, even if the key is either 'KeyType' or 'ValueType'. If you want to set one of the types without specifying data you have to explicitly set both types to make it clear you're setting the types.
Note that if you wanted to create an object with two keys, both 'KeyType' and 'ValueType', you could specify a cell array of keys and values.
c = containers.Map({'KeyType', 'ValueType'}, {1, 2})
keys(c)
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Logical 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
