B =
Why do I get conj(L)
显示 更早的评论
When I multiply 2 4X4 matrices one numeric the other alpha numeric say with L1,L2,L3, L4 why do I get the answer with cconj(L1,L2,L3,L4)? Also why do I get answers in fractions not decimal?
采纳的回答
Star Strider
2025-3-1
0 个投票
The Symbolic Math Toolbox assumes all variables are complex, so it adds the conj to be complete. Specifying that the variables are real in the syms declaration prevents that.
1 个评论
Walter Roberson
2025-3-1
Symbolic Math toolbox does not ordinarily add conj() for matrix multiplication or element-by-element multiplication.
更多回答（1 个）
You probably used the ' operator on the symbolic vector. For example,
syms L [1 4]
A = [2 3; 4 5]/7
B = [L1 L2; L3 L4]
C = A*B
C = A*B'
whereas you might have wanted
D = A*B.'
To get the answer in decimal, either use
vpa(D, 10)
or else use
sympref('FloatingPointOutput', true)
D
类别
在 帮助中心 和 File Exchange 中查找有关 Common Operations 的更多信息
产品
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
