determine if a datetime value is on a different day

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If I have two datetime values, t1 and t2, how can I determine if t2 is on a different, and later, day than t1? The check needs to account for end-of-month and end-of-year rollovers, and the times (hr, min, sec) may not be the same between t1 and t2. I just need to know if they are are different calendar days.
Functions like between and caldiff seem to return a duration, but if that duration is less than 24 hours, this method won't work. For example, two times only 2 minutes apart but accoss a day boundary:
t1 = datetime('2025-03-01 23:59:00')
t1 = datetime
01-Mar-2025 23:59:00
t2 = datetime('2025-03-02 00:01:00')
t2 = datetime
02-Mar-2025 00:01:00
dt = caldiff([t2 t1],'days')
dt = calendarDuration
0d
between(t1,t2,'days')
ans = calendarDuration
0d
datenum would work, but MATLAB is recommending not to use. How can this be done with datetime values and functions?

采纳的回答

Stephen23
Stephen23 2025-3-3
编辑:Stephen23 2025-3-3
"Functions like between and caldiff seem to return a duration"
BETWEEN and CALDIFF will not help you. Either use DATESHIFT or the properties of the DATETIME object:
t1 = datetime('2025-03-01 23:59:00')
t1 = datetime
01-Mar-2025 23:59:00
t2 = datetime('2025-03-02 00:01:00')
t2 = datetime
02-Mar-2025 00:01:00
dateshift(t1,'start','day')==dateshift(t2,'start','day')
ans = logical
0
t1.Year==t2.Year && t1.Month==t2.Month && t1.Day==t2.Day
ans = logical
0
  2 个评论
Tim
Tim 2025-3-3
Ah, dateshift. That's a new one. I'm still learning all of the datetime functions. Thanks!
Peter Perkins
Peter Perkins 2025-3-3
There's also this, if you are already doing something else with the time-of-day:
[T,D] = timeofday(DT) also returns the date portions of the values in DT as the datetime array D.
The output argument D is equivalent to dateshift(DT,'start','day').
dt = datetime;
[~,day] = timeofday(dt)
day = datetime
03-Mar-2025

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更多回答(1 个)

Walter Roberson
Walter Roberson 2025-3-3
t1 = datetime('2025-03-01 23:59:00')
t1 = datetime
01-Mar-2025 23:59:00
t2 = datetime('2025-03-02 00:01:00')
t2 = datetime
02-Mar-2025 00:01:00
t2 >= t1 & dateshift(t1, 'start', 'day') == dateshift(t2, 'start', 'day')
ans = logical
0

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