Displaying non existant array elements
显示 更早的评论
Why am I getting repeating numbers for the array x as an output for the following piece of script?
x=1:0.5:5;
for i=1:length(x);
y(i)=x(i)^2;
end
fprintf(' x y\n')
Results=[x;y];
fprintf('%10.0f %38.16f\n', Results);
1 个评论
Stephen23
2025-3-8
“Why am I getting repeating numbers for the array x as an output for the following piece of script?”
You are not getting the same values repeating in x. You just confused how values are displayed with the values stored in memory. Try printing the values of x with e.g. two decimal places. Then tell us what you see.
采纳的回答
x=1:0.5:5;
for i=1:length(x);
y(i)=x(i)^2;
end
fprintf(' x y\n')
Results=[x;y];
fprintf('%10.2f %38.2f\n', Results);
Because the '%10.0f' required rounding the x values to display integer values...
2 个评论
Ali Kiral
2025-3-8
No problem...as @Stephen23 notes directly and my response says same thing indirectly, you have to remember the difference between what the variable value and its representation may be.
BTW, you do recognize that with MATLAB array syntax you can eliminate the need for the for...end loop in the above, right?
x=1:0.5:5;
y=x.^2;
Results=[x;y];
fprintf('%10s%38s\n','x','y')
fprintf('%10.2f %38.2f\n', Results);
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Resizing and Reshaping Matrices 的更多信息
Translated by 
