How to do inline function with unique instead of using for loop

7 次查看（过去 30 天）
Pete sherer
Pete sherer 2025-5-17
编辑： Matt J 2025-5-18
tdata = table([1 1 1 3 4 4 4 4]', ["eq","fr","wt","fl","eq","fr","fl","tr"]', [24 55 10 5 3 5 7 9 ]', int64([ 5 2 7 1 50 10 5 5 ]'),...
'VariableNames',["EBID","Peril","Loss","Trial"]);
refGrp = [ "EBID"];
[ uniqEBID, ~, JGrp]= unique( tdata( :, refGrp));
uniqEBID.maxLoss = accumarray( JGrp, tdata.Loss, [], @max);
instead of doing for loop below, can we use inline function with accumarray to do task below. Basically selecting other fields that has same index as maxLoss
for runi= 1: height( uniqEBID_Type)
tloc = (JGrp== runi);
tdata_i = tdata( tloc, :);
[ tmax, idx]= max( tdata_i.Loss);
uniqEBID.Peril( runi) = tdata_i.Peril( idx);
uniqEBID.Trial( runi) = tdata_i.Trial( idx);
end

请先登录，再回答此问题。

采纳的回答

Matt J
Matt J 2025-5-17
编辑：Matt J 2025-5-18
Ran in:
If by "inline function", you mean an anonymous function, then no. But you can certainly do it with a local function.
tdata = table([1 1 1 3 4 4 4 4]', ["eq","fr","wt","fl","eq","fr","fl","tr"]', [24 55 10 5 3 5 7 9 ]', int64([ 5 2 7 1 50 10 5 5 ]'),...
'VariableNames',["EBID","Peril","Loss","Trial"]);
refGrp = [ "EBID"];
uniqEBID=splitapply(@aggregate, tdata, findgroups(tdata.(refGrp)) )
uniqEBID = 3×4 table
EBID Peril maxLoss Trial ____ _____ _______ _____ 1 "fr" 55 2 3 "fl" 5 1 4 "tr" 9 5
function out=aggregate(EBID,Peril,Loss,Trial)
[maxLoss,idx]=max(Loss);
out=table(EBID(idx),Peril(idx), maxLoss,Trial(idx), ...
'Var',{'EBID','Peril', 'maxLoss','Trial'});
end

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Function Creation 的更多信息

标签

产品


版本

R2024b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by