istable() returns false for my table

2025 7 15
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更新时间：2025 7 16
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I create a table under certain conditions, later want to check if it is a table yet.
Checking in the command window I get this
K>> (app.Results2Table)
ans =
Columns 1 through 5
643705 644260 644760 645000 0
646934 647489 647989 648229 0
650201 0 0 0 0
K>> istable(app.Results2Table)
ans =
logical
0
Looks like a table to me

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Les Beckham
Les Beckham 2025-7-15
移动：Walter Roberson 2025-7-15

0 个投票

That is definitely not a table. You can confirm that with the whos command. Tables are formatted differently when displayed. Specifically, they have variable names (that look like column titles).

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Les Beckham
Les Beckham 2025-7-15
移动：Walter Roberson 2025-7-15
Ran in:
Ran in:
For example:
T = array2table(rand(5))
T = 5×5 table
Var1 Var2 Var3 Var4 Var5 _______ _________ _______ _________ ________ 0.72169 0.44067 0.54442 0.51337 0.98782 0.36857 0.0020561 0.42387 0.19171 0.71103 0.60238 0.41035 0.83338 0.0030115 0.37504 0.57584 0.21747 0.86724 0.93166 0.15564 0.13459 0.56578 0.62416 0.53486 0.057996
Gavin
Gavin 2025-7-15
So it's not a table until I put the header on it even if I declare it as a table at the start. It's a matrix? I changed the check to ~isempty() and that works.
Thanks, that had me stumped.
Steven Lord
Steven Lord 2025-7-16
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Ran in:
How exactly did you try to declare it as a table? What command did you use?
If you preallocated it to contain a certain amount of data like the following, that makes it an array (or since this is 2-dimensional, a matrix as per the definition used by the ismatrix function.) All table arrays are matrices, but it is not the case that all matrices or all arrays are tables.
a = zeros(5) % matrix and array, but not a table
a = 5×5
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
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Or if you did this, that makes it a cell array not a table.
b = {1, 2, 3, 4, 5}
b = 1×5 cell array
{[1]} {[2]} {[3]} {[4]} {[5]}

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