istable() returns false for my table

3 次查看(过去 30 天)
I create a table under certain conditions, later want to check if it is a table yet.
Checking in the command window I get this
K>> (app.Results2Table)
ans =
Columns 1 through 5
643705 644260 644760 645000 0
646934 647489 647989 648229 0
650201 0 0 0 0
K>> istable(app.Results2Table)
ans =
logical
0
Looks like a table to me

采纳的回答

Les Beckham
Les Beckham 2025-7-15
移动:Walter Roberson 2025-7-15
That is definitely not a table. You can confirm that with the whos command. Tables are formatted differently when displayed. Specifically, they have variable names (that look like column titles).
  3 个评论
Gavin
Gavin 2025-7-15
So it's not a table until I put the header on it even if I declare it as a table at the start. It's a matrix? I changed the check to ~isempty() and that works.
Thanks, that had me stumped.
Steven Lord
Steven Lord 2025-7-16
How exactly did you try to declare it as a table? What command did you use?
If you preallocated it to contain a certain amount of data like the following, that makes it an array (or since this is 2-dimensional, a matrix as per the definition used by the ismatrix function.) All table arrays are matrices, but it is not the case that all matrices or all arrays are tables.
a = zeros(5) % matrix and array, but not a table
a = 5×5
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
Or if you did this, that makes it a cell array not a table.
b = {1, 2, 3, 4, 5}
b = 1×5 cell array
{[1]} {[2]} {[3]} {[4]} {[5]}

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Tables 的更多信息

标签

产品


版本

R2024b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by