Modulo with expression not the same as modulo with value

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James
James 2025-7-18
编辑： James 2025-7-18
Ran in:
Why does mod(1, Y-X) not approximately equal 0?
mod(1, 0.1)
ans = 0
X = 2;
Y = 2.1;
Y - X
ans = 0.1000
mod(1, Y - X)
ans = 0.1000
I realize that Y - X ~= 0.1 but
isapprox(Y - X, 0.1, "loose")
ans = logical
1
therefore, why not
isapprox(mod(1, Y - X), 0, "loose")
ans = logical
0
My guess is that it is either something to do with floating point precision or the fact that it is an expression vs. a value?

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采纳的回答

Matt J
Matt J 2025-7-18
编辑：Matt J 2025-7-18
Ran in:
Because mod(1,z) is a discontinuous function of z at 0.1,
fplot(@(z) mod(1,z),[0,0.2])
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