Modulo with expression not the same as modulo with value
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Why does mod(1, Y-X) not approximately equal 0?
mod(1, 0.1)
X = 2;
Y = 2.1;
Y - X
mod(1, Y - X)
I realize that Y - X ~= 0.1 but
isapprox(Y - X, 0.1, "loose")
therefore, why not
isapprox(mod(1, Y - X), 0, "loose")
My guess is that it is either something to do with floating point precision or the fact that it is an expression vs. a value?
采纳的回答
Because mod(1,z) is a discontinuous function of z at 0.1,
fplot(@(z) mod(1,z),[0,0.2])
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