PREDICT NEW FONCTION WITH DEEP LEARNING
显示 更早的评论
I want to find a function h that does not depend on aztan
I have this function
h=acos((sin(w*pi/180)*cos(de))/sin(aztan))
where
aztan=atan(sin(w*pi/180)/(sin(phir)*cos(w*pi/180)-cos(phir)*tan(de)))
w=hour angle, de=declinaison, aztan=azimut, phir=lattitude
1 个评论
Can you just do this:
w = 2.3; % [deg] hour angle
de = deg2rad(65); % [rad] declination angle
phir = deg2rad(45); % [rad] latitude
h=acos((sind(w)*cos(de))/sin(atan2(sind(w),(sin(phir)*cosd(w)-cos(phir)*tan(de)))))
回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Design of Experiments (DOE) 的更多信息
2025-8-1
2025-8-8
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
