Identify postion in a date vector

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Inês Mendes 2015-5-21

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https://ww2.mathworks.cn/matlabcentral/answers/217963-identify-postion-in-a-date-vector

评论： Star Strider 2015-5-23

采纳的回答： Star Strider

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Hiii,

I am trying to identify the index of the day and month in a date string.

I used datevec and now I have an array with date strings like this:

x= [09-12-2014 07:45
09-12-2014 08:00
09-12-2014 08:15
09-12-2014 08:30]

I want to identify the position of the day and month but I am not being able to do so..

Can anyone help?

Inês

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Answer 1

Star Strider 2015-5-21

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Actually, you used datestr not datevec although datevec would make your task much easier.

This works:

x= ['09-12-2014 07:45'
    '09-12-2014 08:00'
    '09-12-2014 08:15'
    '09-12-2014 08:30'];
[day, mon] = strread(x', '%2d-%2d-%-*4d %*2d:%*2d');

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Inês Mendes 2015-5-23

编辑：Star Strider 2015-5-23

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if i have an interface in which a user chooses a day and month, how do i extract only the data from that date?

Imagine I have:

x= ['08-11-2014 07:45'
    '10-12-2014 08:00'
    '09-12-2014 08:15'
    '09-12-2014 08:30'];

and

If the user choose to study November 8th how do i extract only Y=[2].

Can you help?

Thanks!

Star Strider 2015-5-23

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My pleasure!

This may be a bit more than you asked for, but this is how I would do it (using the listbox and msgbox functions because I like the GUI dialogue functions):

x= ['08-11-2014 07:45'
    '10-12-2014 08:00'
    '09-12-2014 08:15'
    '09-12-2014 08:30'];
Y= [2
    5
    6
    7];
[dateidx,v] = listdlg('PromptString','Select a date', 'SelectionMode', 'Single', 'ListString',x);
msgbox(sprintf('The value corresponding to %s is %0.2f',x(dateidx,:),Y(dateidx)), 'Result');