Identify postion in a date vector

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Inês Mendes
Inês Mendes 2015-5-21
评论： Star Strider 2015-5-23
Hiii,
I am trying to identify the index of the day and month in a date string.
I used datevec and now I have an array with date strings like this:
x= [09-12-2014 07:45
09-12-2014 08:00
09-12-2014 08:15
09-12-2014 08:30]
I want to identify the position of the day and month but I am not being able to do so..
Can anyone help?
Inês

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Star Strider
Star Strider 2015-5-21
Actually, you used datestr not datevec although datevec would make your task much easier.
This works:
x= ['09-12-2014 07:45'
'09-12-2014 08:00'
'09-12-2014 08:15'
'09-12-2014 08:30'];
[day, mon] = strread(x', '%2d-%2d-%-*4d %*2d:%*2d');
  2 个评论
Inês Mendes
Inês Mendes 2015-5-23
编辑：Star Strider 2015-5-23
if i have an interface in which a user chooses a day and month, how do i extract only the data from that date?
Imagine I have:
x= ['08-11-2014 07:45'
'10-12-2014 08:00'
'09-12-2014 08:15'
'09-12-2014 08:30'];
and
Y=[2
5
6
7]
If the user choose to study November 8th how do i extract only Y=[2].
Can you help?
Thanks!
Star Strider
Star Strider 2015-5-23
My pleasure!
This may be a bit more than you asked for, but this is how I would do it (using the listbox and msgbox functions because I like the GUI dialogue functions):
x= ['08-11-2014 07:45'
'10-12-2014 08:00'
'09-12-2014 08:15'
'09-12-2014 08:30'];
Y= [2
5
6
7];
[dateidx,v] = listdlg('PromptString','Select a date', 'SelectionMode', 'Single', 'ListString',x);
msgbox(sprintf('The value corresponding to %s is %0.2f',x(dateidx,:),Y(dateidx)), 'Result');

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