I have a bug on my code
显示 更早的评论
It keeps saying u(t) is not defined even though I did.
% t bounded between -1 and 1 with a step of 0.01
t = -1:0.01:1;
%Plot on a graph
x_1 = 5 * u(t-0.1);
x_2 = 2 * rectangularPulse(t/0.3);
x_3 = 4 * sinc(t/0.2);
figure
plot(t,x1,'g',t,x2fx,'b',t,x3,'c');
% Label the graph
xlabel('Amplitude')
ylabel('Time t[s]')
title('Assignment 3')
legend("x1(t)","x2(t)","x3(t)");
grid on;
% Step function implementing 𝑦(𝑡) = 𝑢(𝑡)
function y =u(t)
y(t > 0) = 1;
y(t == 0) = 0.5;
y(t < 0) = 0;
end
% Rectangular pulse function implementing 𝑦(𝑡) = Π(𝑡)
function y = rectangularPulse(t)
y = (t >= -0.5 & t <= 0.5);
end
% Sinc function implementing 𝑦(𝑡) = 𝑠𝑖𝑛𝑐(𝑡)
function y = sinc(t)
y = (sin(pi.*t) / pi.*t);
end
1 个评论
You have not defined the following variables/functions: x1, x2fx, x3.
Once you define those variables then your code works:
% t bounded between -1 and 1 with a step of 0.01
t = -1:0.01:1;
%Plot on a graph
x1 = 5 * u(t-0.1); % fixed name
x2 = 2 * rectangularPulse(t/0.3); % fixed name
x3 = 4 * sinc(t/0.2); % fixed name
figure
plot(t,x1,'g',t,x2,'b',t,x3,'c');
% Label the graph
xlabel('Amplitude')
ylabel('Time t[s]')
title('Assignment 3')
legend("x1(t)","x2(t)","x3(t)");
grid on;
% Step function implementing 𝑦(𝑡) = 𝑢(𝑡)
function y = u(t)
y(t > 0) = 1;
y(t == 0) = 0.5;
y(t < 0) = 0;
end
% Rectangular pulse function implementing 𝑦(𝑡) = Π(𝑡)
function y = rectangularPulse(t)
y = (t >= -0.5 & t <= 0.5);
end
% Sinc function implementing 𝑦(𝑡) = 𝑠𝑖𝑛𝑐(𝑡)
function y = sinc(t)
y = (sin(pi.*t) / pi.*t);
end
回答（1 个）
Image Analyst
2025-9-14
0 个投票
You have not defined x1. x1 is a differently-named variable than x_1.
- If they should be the same variable, then use a consistent name, either with or without the underline.
- Otherwise if they are different variables you need to define exactly what x1 is.
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2025-9-14
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