Counting the number 6s rolled from a dice

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Nathan
Nathan 2025-10-16
编辑： Torsten 2025-10-16
I was trying to get my code to count the number of 6s rolled from 1000 attempts from a dice however it keeps saying it has not rolled a single 6.
X= floor(rand(1,1000)*6)+1;
if X==6
y = y + 1
end
y
>> Week3Q1
y =
0
Why does it display 0 even though a 6 must have been rolled? Help would be appreciated.

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Dyuman Joshi
Dyuman Joshi 2025-10-16
编辑：Dyuman Joshi 2025-10-16
Ran in:
You can also use randi to generate the data as well -
X = randi([1 6], 1, 1000);
The "if" statement is only executed when all of the inputs are true -
if [true false]
disp('Hey')
elseif [true true true]
disp('Hello')
end
Hello
What you want to do is to go through each value in X and compare it to 6 -
y = 0;
for k=1:numel(X)
if X(k)==6
y = y+1;
end
end
y
y = 183
You can also do it directly like this -
Y = sum(X==6)
Y = 183
%or
Y = nnz(X==6)
Y = 183
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Torsten
Torsten 2025-10-16
编辑：Torsten 2025-10-16
Ran in:
@Nathan
If you want to use "rand" to simulate your experiment, you can interprete the event that "rand" gives a value in between 5/6 and 1 as a "six" for the dice roll.
rng("default")
X = rand(1,10000);
n = nnz(X >= 5/6);
n/10000
ans = 0.1639
1/6
ans = 0.1667

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