Taking part in the boundary calculation from the function

2026 6 24
1 个回答
回答已采纳
更新时间：2026 6 24
25 次查看（30 天）

0 个投票

Dear All,
I have a question regarding optimization calculations. I would like one of the boundary variables (M) to be calculated from the main function. Specifically, I have a program where I want to determine the value of M using the main function , and I would like to set this value as the upper boundary. Additionally, this value of M will change in each iteration based on the suggested value of x.
function [EFFT]=optimizpandy(x)
A1=x(1);
A2=x(2);
A3=x(3);
M=A1+A2;
EFFT=A1+A2^2+A3;
end
x0=[0.0019998 0.023 0.0019998 ];
lb=[0.001 0.02 0.001 ];
ub=[0.004 0.08 (M)-0.0001 ];
x= fmincon(@optimizpandy,x0,[],[],[],[],lb,ub);

请先登录，再回答此问题。

 采纳的回答

Steven Lord
Steven Lord 2026-6-24

1 个投票

So you want to ensure that x(3) <= x(1)+x(2)-0.0001? That's not a bound, that's a linear constraint.
Write it as -x(1)-x(2)+x(3) <= -0.0001 and specify it using the A and b inputs to fmincon.

4 个评论
显示 2更早的评论 隐藏 2更早的评论

mohammed hussein
mohammed hussein 2026-6-24
Thank you for your reply and suggestion . I want M to be calculated during the optimization process. My program is more complex than this example. Although this example may seem easy, I use it only to explain my problem.
Torsten
Torsten 2026-6-24
编辑：Torsten 2026-6-24
Ran in:
Ran in:
lb and ub for x(3) must be constants and mustn't depend on solution variables. As correctly noted by @Steven Lord, you have to formulate this restriction as a linear constraint:
x0 = [0.0019998 0.023 0.0019998 ];
lb = [0.001 0.02 0.001 ];
ub = [0.004 0.08 Inf ];
A = [-1 -1 1];
b = -0.0001;
x = fmincon(@optimizpandy,x0,A,b,[],[],lb,ub)
Local minimum found that satisfies the constraints. Optimization completed because the objective function is non-decreasing in feasible directions, to within the value of the optimality tolerance, and constraints are satisfied to within the value of the constraint tolerance.
x = 1×3
0.0010 0.0200 0.0010
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
function [EFFT]=optimizpandy(x)
A1=x(1);
A2=x(2);
A3=x(3);
EFFT=A1+A2^2+A3;
end
Matt J
Matt J 2026-6-24
编辑：Matt J 2026-6-24
I want M to be calculated during the optimization process. My program is more complex than this example.
If you mean that M(x) is, more generally, a nonlinear function of x, then the constraints are nonlinear, and you must express them using the nonlcon argument,
mohammed hussein
mohammed hussein 2026-6-24
I will try to use this note. Thank you!

请先登录，再进行评论。

更多回答（0 个）

类别

在 帮助中心 和 File Exchange 中查找有关 Solver Outputs and Iterative Display 的更多信息

产品

版本

R2025a

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by