datetime format with T time demarcation
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I have data that I've read in with datetime format that includes a T such as:
>> ais_data.BaseDateTime(3)
ans =
datetime
2023-08-01T11:07:56
If I change the value, how do I format the answer. For example, I would like to increment the minute, like such 2023-08-01T11:08:56
However, this results in the following error
>> datetime(2023-08-01T11:08:56)
datetime(2023-08-01T11:08:56)
↑
Error: Unexpected 'T11'. Check for missing multiplication operator.
How do make a datetime number like the one I'm seeing in the example at the top?
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dt1 = datetime(2023,8,1,11,07,56, "Format","yyyy-MM-dd'T'HH:mm:ss")
dt2 = dt1 + minutes(1)
采纳的回答
You're trying to convert a string representation so it has to be a string variable of some type... (+)
datetime('2023-08-01T11:08:56')
If you have a datetime variable already, then increment it instead of trying to convert..
ais_data.BaseDateTime=datetime('2023-08-01T11:07:56')
newDateTime=ais_data.BaseDateTime+minutes(1)
(+) If you have a value as datetime, to convert the string representation would be
ais_data.BaseDateTime.Format='yyyy-MM-dd''T''HH:mm:ss'; % default format doesn't include T
date_str=string(ais_data.BaseDateTime)
datetime(date_str)
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