3D Gaussian Decay from 1 to 0

Question

Inês Rodrigues 2015-5-26

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/218591-3d-gaussian-decay-from-1-to-0

评论： Inês Rodrigues 2015-5-26

I'm doing a model in matlab and I want that, when my variable k is 1, it decays to 0 by a gaussian pattern. It's a 3D model, so the maximum 1 would decay in every direction. The result would be a matrix with the ones k gave me and the other elements between 0 and 1. Could you please help me?

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Image Analyst 2015-5-26

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/218591-3d-gaussian-decay-from-1-to-0#answer_180396

编辑：Image Analyst 2015-5-26

If you have the Image Processing Toolbox, you can use fspecial(). Of course since it's Gaussian, it will decay towards zero, not to zero. Gaussians can never equal zero.

If you don't have that toolbox, just use meshgrid() and exp() to create the Gaussian pattern. In fact, this might be easier for the 3D case since with fspecial, it just creates a 2D Gaussian so you'd have to call it repeatedly to get the third dimension of a 3D Gaussian "ball".

3 个评论
显示 1更早的评论隐藏 1更早的评论

Image Analyst 2015-5-26

Of course, just use x - xCenter. The usual offset formula like for all mathematical formula like you're used to. But you're not creating a 3D matrix, you're creating a 2D one. Just look - 2 indexes. That means it's 2D. If it were 3D, you'd have to have 3 indexes, one for x, one for y, and one for z.

Inês Rodrigues 2015-5-26