Accept 2 numbers from user
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This is my current code. how do i add this part of my algorithm into matlab code
integer :: a, b, c
integer :: abc, a3b3c3
integer :: count
count = 0
count = count + 1
clc
num1 = input('Enter num1 value: ');
num2= input('Enter num2 value: ');
fprintf('Armstrong numbers between %d and %d are: \n',num1 ,num2);
for a = 1 : 9
for b = 0 : 9
for c = 0 : 9
n = a*100 + b*10 + c;
an = a^3 + b^3 + c^3;
if n == an
fprintf('%d, ',an)
end
end
end
end
回答（1 个）
Andrei Bobrov
2015-5-27
编辑：Andrei Bobrov
2015-5-27
a1 = 1 : 9;
b1 = 0 : 9;
c1 = 0 : 9;
num1 = input('Enter num1 value: ');
num2= input('Enter num2 value: ');
[c,b,a] = ndgrid(c1,b1,a1);
n = a*100 + b*10 + c;
an = a^3 + b^3 + c^3;
t1 = n >= num1 & n <= num2;
t2 = an == n;
out = an(t1 & t2);
3 个评论
Josaiah Ang
2015-5-27
Josaiah Ang
2015-5-27
a1 = 1 : 9;
b1 = 0 : 9;
c1 = 0 : 9;
num1 = input('Enter num1 value: ');
num2= input('Enter num2 value: ');
[c,b,a] = ndgrid(c1,b1,a1);
n = a*100 + b*10 + c;
an = a.^3 + b.^3 + c.^3;
t1 = n >= num1 & n <= num2;
t2 = an == n;
out = an(t1 & t2);
i'm getting the output like this. it not displaying any result.
Walter Roberson
2015-5-27
The calculation for Armstrong numbers depends upon the number of digits. The program is for 3 digit Armstrong numbers only. You are trying to find some 1 digit Armstrong numbers and some 2 digit Armstrong numbers. Your algorithm needs to be changed for that.
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2015-5-27
2015-5-27
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