To accept two numbers from the user; Display all prime numbers between these two numbers.

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BeTrayer EK
BeTrayer EK 2015-5-28
评论： BeTrayer EK 2015-5-28
To accept two numbers from the user; Display all prime numbers between these two numbers.
To accept two numbers from the user and display perfect numbers between these two numbers.
To accept two numbers from the user and display Armstrong number between these numbers.
Simple coding using DoWhile, IfElse

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采纳的回答

B.k Sumedha
B.k Sumedha 2015-5-28
编辑：Andrei Bobrov 2015-5-28
clc
num1 =input('Enter num1 value ');
num2 =input('Enter num2 value ');
n = num1 : num2;
p = isprime(n);
n(p) %displays the primes
  1 个评论
BeTrayer EK
BeTrayer EK 2015-5-28
Hi if lets say my matlab dont have the "isprime" how do i do with it ?
How about these 2 more
To accept two numbers from the user and display perfect numbers between these two numbers.
To accept two numbers from the user and display Armstrong number between these numbers.
*thank you for reply and taking your time to read it . very appreciated*

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更多回答（2 个）

B.k Sumedha
B.k Sumedha 2015-5-28
Try this for Armstrong number:
clear, clc
% Let i take two numbers say 100 to 999
for i = 100 : 999
% We examine every digit in i
is = num2str(i);
% i1 is the left-most digit in i
i1 = str2num(is(1));
% i2 is the middle digit
i2 = str2num(is(2));
% i3 is the right-most digit in i
i3 = str2num(is(3));
% We calculate the probable AN
an = i1^3 + i2^3 + i3^3;
% We compare to the number itself
if i == an
% We display the pair of equal numbers
disp([i an])
end
end
B.k Sumedha
B.k Sumedha 2015-5-28
This is for perfect numbers where u can change the values of m and n where they are the two input numbers
n=100;
m=10;
output = zeros(1,n);
for i = m:n
test = 1:i-1;
if (sum(test(mod(i,test) == 0)) == i)
output(i) = i;
end
end
output(output == 0) = []
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BeTrayer EK
BeTrayer EK 2015-5-28
Thank you very much B.k Sumedha for answering & taking your time to reply .
but if let say i want the user to input the value any more simple breakdown way i can use ?
Thank you
BeTrayer EK
BeTrayer EK 2015-5-28
My method for doing single is like that . lets say i want double ?
clear clc
Key=0; Num1 = input('Enter A Number :'); Num2 = input('Enter A Number:'); Count = 1;
while(Count<=Num1)
if (rem(Num1,Num2,Count)==0)
Key=Key+1;
end
Count = Count + 1;
end
if(Key==2)
fprintf('%d Is A Prime Number\n' ,Num1);
else
fprintf('%d NOT A Prime Number\n', Num1);
end

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