Partial Differentiation of a function
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syms x y
f=x^2+2*y^2-22
P=diff(f,x)
Here, I have calculated the (partial) differentiation of function "f" w.r.t 'x'
Now, I want to know the value of 'P' at certain point (say x=1.5, y=2.0)
Please help!
1 个评论
Jimmy
2023-10-13
The information you share is necessary for me, I've been looking for it for a few days and it helped me get my job done.
采纳的回答
Grzegorz Knor
2011-11-23
One of the possibilities:
syms x y
f=x^2+2*y^2-22
P=diff(f,x)
subs(P,{x,y},{1.5,2})
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