Too many output arguments error in my code

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Robert
Robert 2015-6-2
编辑： Stephen23 2015-6-2
I have the following code, I am trying to get all of the wavelet approximations out (it works fine with details, but not approximations).
I know what the error means, I just can't figure out how it applies in my code.
GRACE = load ('GRACE.txt')
ncol = size(GRACE,2);
for k = 1:ncol
[c,l] = wavedec(GRACE(:,k),6,'dmey');
cA6 = appcoef(c,l,'dmey',6);
[cD1,cD2,cD3,cD4,cD5,cD6] = appcoef(c,l,[1,2,3,4,5,6]);
D = [];
D(:,6) = wrcoef('d',c,l,'dmey',6);
D(:,5) = wrcoef('d',c,l,'dmey',5);
D(:,4) = wrcoef('d',c,l,'dmey',4);
D(:,3) = wrcoef('d',c,l,'dmey',3);
D(:,2) = wrcoef('d',c,l,'dmey',2);
D(:,1) = wrcoef('d',c,l,'dmey',1);
filename = sprintf('%s_%04f.txt', 'GRACE_APROXIMATIONS', k)
csvwrite(filename,D)
end
Any help would be greatly appreciated

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回答（1 个）

Walter Roberson
Walter Roberson 2015-6-2
编辑：Walter Roberson 2015-6-2
appcoef() only ever returns one variable. You are trying to get it to return 6.
If you are not passing a string representing the wavelet name, then you should be using either 4 or 5 arguments, with the 3rd and 4th being filters. Your [1,2,3,4,5,6] is being interpreted as a filter.
You cannot pass in a list of levels and get one output variable for each.
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Robert
Robert 2015-6-2
So something like this? This is my best interpretation of what you suggest, Still I get the same error, am I on the right path?
GRACE = load ('GRACE.txt')
ncol = size(GRACE,2);
for k = 1:ncol
[c,l] = wavedec(GRACE(:,k),6,'dmey');
cA1 = appcoef(c,l,'dmey',1);
cA2 = appcoef(c,l,'dmey',2);
cA3 = appcoef(c,l,'dmey',3);
cA4 = appcoef(c,l,'dmey',4);
cA5 = appcoef(c,l,'dmey',5);
cA6 = appcoef(c,l,'dmey',6);
[cA1,cA2,cA3,cA4,cA5,cA6] = appcoef(c,l,[1,2,3,4,5,6]);
D = [];
D(:,6) = wrcoef('d',c,l,'dmey',6);
D(:,5) = wrcoef('d',c,l,'dmey',5);
D(:,4) = wrcoef('d',c,l,'dmey',4);
D(:,3) = wrcoef('d',c,l,'dmey',3);
D(:,2) = wrcoef('d',c,l,'dmey',2);
D(:,1) = wrcoef('d',c,l,'dmey',1);
filename = sprintf('%s_%04f.txt', 'GRACE_APROXIMATIONS', k)
csvwrite(filename,D)
end
if true
% code
end
Stephen23
Stephen23 2015-6-2
编辑：Stephen23 2015-6-2
@Robert: the appcoef documentation shows these syntaxes:
A = appcoef(C,L,'wname',N)
A = appcoef(C,L,'wname')
A = appcoef(C,L,Lo_R,Hi_R)
A = appcoef(C,L,Lo_R,Hi_R,N)
Count the outputs: each syntax shows exactly one output. You wrote this:
[cA1,cA2,cA3,cA4,cA5,cA6] = appcoef(c,l,[1,2,3,4,5,6]);
Count the outputs: there are six of them. The error message is telling you that you have too many outputs for this function: appcoef provides only one output.
To fix this you have to call appcoef in a loop, as Walter Roberson wrote.

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