清空筛选条件
清空筛选条件

how to make a function that return cell array of the month

6 次查看（过去 30 天）
Muhammad Usman Saleem
评论： Muhammad Usman Saleem 2015-6-8
Hi every one;
I am going to attempt that query:
Write a function called June2015 that returns a cell array of dimensions 30-by-3, whose rows correspond to the days of June, 2015. The three elements of each row must be set as follows:
• The first element refers to the string 'June' (uppercase ‘J’). • The second element refers to a scalar of type double that equals the date (1 through 30). • The third element refers to the three-letter abbreviation of the day chosen from this list: 'Mon', 'Tue', 'Wed', 'Thu', 'Fri', 'Sat', 'Sun'.
For example, here is a call of the function followed by a command that shows the eleventh element of the cell array that is returned by the function:
>> m = June2015;
>> m(11,:)
ans =
'June' [11] 'Thu'
I am using that code
function m = June2015
A=cell(30,3)%declar cell array of 30 by 3
for i = 1:30
[DateNumber, DateName] = weekday(datenum([2015 6 i]));% making the value of DateNume for DateNumber
%and loop run number of rows in cell array
for j=1:3% loop run for column of cell array
A(i,:)={'June', i, 'DateName'}
end
end
end
but in testing i am getting that error
Your solution is _not_ correct.
Guide me about my corrections.. thanks in advance
  8 个评论
显示 6更早的评论
Christos Vyzantios
Christos Vyzantios 2015-6-5
编辑：Walter Roberson 2015-6-8
I transform liitle the code but the problem exist
function m = June2015 %#ok<STOUT>
A=cell(30,3);%declar cell array of 30 by 3
for i = 1:30 %#ok<ALIGN>
[~, DateName] = weekday(datenum([2015 6 i]));
A(i,:) = {'June', i, DateName};
end
end
Muhammad Usman Saleem
Muhammad Usman Saleem 2015-6-7
@Christos Vyzantios i have formatted your code but i am getting below mentioned error
function m = June2015 %#ok<STOUT>
A=cell(30,3);%declar cell array of 30 by 3
for i = 1:30 %#ok<ALIGN>
[~, DateName] = weekday(datenum([2015 6 i]));
A(i,:) = {'June', i, 'DateName'};
end
end
error i get
Your solution is _not_ correct.
Please correct my code. Thanks in advance for that...

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Walter Roberson
Walter Roberson 2015-6-2
In your line
A(i,:)={'June', i, 'DateName'}
that would attempt to put the literal string 'DateName' into the array, rather than trying to put any content from the variable DateName into the array.
You probably want to select a portion of DateName rather than the whole thing.
  3 个评论
显示 1更早的评论

请先登录，再进行评论。

更多回答（3 个）

Jan
Jan 2015-6-2
The loop over j is not required. Simply omit it.
The 3rd column of A should not be the string 'DateName(i,:)', but the contents of the variable DateName. So use:
A(i,:) = {'June', i, DateName} ;
  7 个评论
显示 5更早的评论
Walter Roberson
Walter Roberson 2015-6-8
编辑：Walter Roberson 2015-6-8
function A = June2015
A=cell(30,3)%declar cell array of 30 by 3
for i = 1:30
[DateNumber, DateName] = weekday(datenum([2015 6 i]));
% making the value of DateNume for DateNumber and loop run number of rows in cell array
[A{i,:}] = deal('June', i, DateName) ;
end
end

请先登录，再进行评论。

abdo desoki
abdo desoki 2015-6-6
change that variable A with m and it will run correctly .
  1 个评论
Muhammad Usman Saleem
Muhammad Usman Saleem 2015-6-7
@abdo , i use that but error remains same
function m = June2015
m=cell(30,3)%declar cell array of 30 by 3
for i = 1:30
[DateNumber, DateName] = weekday(datenum([2015 6 i]));
% making the value of DateNume for DateNumber and loop run number of rows in cell array
m(i,:) = {'June', i, 'DateName'} ;
end
end
that error is come the code
Your solution is _not_ correct.

请先登录，再进行评论。

Luxman Maheswaran
You have to convert the number of DateName to a string such as 'Thu' I have checked it with a grader and it is correct

类别

在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by