why isn´t datevec accepting strings like this one: "12-12-2012 00:00"?

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Inês Mendes
Inês Mendes 2015-6-2
编辑： per isakson 2015-6-4
Hi guys,
I used datevec before but never with a string that points to midnight.
I have an array like this one:
01-06-2014 00:00,
01-06-2014 00:10,
01-06-2014 00:20,
01-06-2014 00:30,
01-06-2014 00:40,
02-06-2014 00:00,
02-06-2014 00:10,
02-06-2014 00:20,
02-06-2014 00:30,
02-06-2014 00:40]
the thing is: datevec doesn´t recognize any of the strings that have 00:00 and i don´t know why...
Does anyone know what to do?
Thanks is advance!
Inês

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Ingrid
Ingrid 2015-6-2
I do not seem to be able to reproduce your problem. Are you sure you are providing strings to datevec (as this is not the case in your example)
datevec({'01-06-2014 00:00', '01-06-2014 00:10', '01-06-2014 00:20',...
'01-06-2014 00:30', '01-06-2014 00:40', '02-06-2014 00:00',...
'02-06-2014 00:10', '02-06-2014 00:20', '02-06-2014 00:30', '02-06-2014 00:40'})
ans =
2014 1 6 0 0 0
2014 1 6 0 10 0
2014 1 6 0 20 0
2014 1 6 0 30 0
2014 1 6 0 40 0
2014 2 6 0 0 0
2014 2 6 0 10 0
2014 2 6 0 20 0
2014 2 6 0 30 0
2014 2 6 0 40 0
  2 个评论
Inês Mendes
Inês Mendes 2015-6-2
yes..i have an excel in which the first column is a column with the date. When I extract it, the first column is a string array..then i try to use datevec and i doesn´t work...if i eliminate the first row it works because matlab doesn´t come across the 00:00 string..the thing is that in the middle of the array i have other 00:00 strings..
Ingrid
Ingrid 2015-6-2
than the problem is not with datevec but with the way the excel data is imported, how do you do this and what is the resulting column?

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