d(phi)/dt=laplaciano(-phi+phi^3-laplaciano(phi)) given boundary conditions and a initial state (strange result)

2 次查看（过去 30 天）

DDD 2015-6-2

评论： DDD 2015-6-2

It is given d(phi)/dt=laplaciano(-phi+phi^3-laplaciano(phi)) to solve in a square 30*30 (L=30).

It is also mentioned that phi(1, y) = 1 and phi(L, y) =

DDD 2015-6-2

It is not accepting the whole question

在 Help Center 和 File Exchange 中查找有关 Ordinary Differential Equations 的更多信息

Find the treasures in MATLAB Central and discover how the community can help you!

Translated by

d(phi)/dt=​laplaciano​(-phi+phi^​3-laplacia​no(phi)) given boundary conditions and a initial state (strange result)