d(phi)/dt=​laplaciano​(-phi+phi^​3-laplacia​no(phi)) given boundary conditions and a initial state (strange result)

1 次查看（过去 30 天）
DDD
DDD 2015-6-2
评论： DDD 2015-6-2
It is given d(phi)/dt=laplaciano(-phi+phi^3-laplaciano(phi)) to solve in a square 30*30 (L=30).
It is also mentioned that phi(1, y) = 1 and phi(L, y) =

请先登录，再回答此问题。

回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Mathematics 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by