Pulling Even numbers from an array

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Gina Barlage
Gina Barlage 2015-6-3
回答： Stephen23 2015-6-3
My assignment was to create a function where it had to count the number of even numbers in the array given and display the count if there were even numbers. This is what I have so far....
function [] = script28_gina_barlage(M)
sum_total = 0;
string1 = ['There are ' num2str(sum_total) ' even numbers.'];
%
for ii = M
if mod(ii,1)==2 & any(ii== M)
sum_total = sum_total + 1;
disp(string1)
else
sum_total = sum_total;
disp('There are no even numbers.')
end
end
I am not sure how to pull out the even numbers. Right now it just repeats 'There are no even numbers.' however many numbers are in the array times.

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回答（2 个）

Image Analyst
Image Analyst 2015-6-3
Close, but you need to mod with 2, not 1, and don't display the total until you're done with the loop:
M = randi(9, 1, 20)
sum_total = 0;
for ii = M
if mod(ii, 2)== 0
sum_total = sum_total + 1;
fprintf('%d is even.\n', ii);
end
end
message = sprintf('There are %d even numbers.', sum_total);
uiwait(helpdlg(message));
Stephen23
Stephen23 2015-6-3
Hers is a simple vectorized function:
function [] = script28_gina_barlage(M)
X = nnz(mod(M(:),2)==0);
if X==0
fprintf('There are no even numbers\n')
else
fprintf('There are %d even numbers\n',X)
end
and tested:
>> script28_gina_barlage([1,2,3,4,5])
There are 2 even numbers
>> script28_gina_barlage(1:2:11)
There are no even numbers
>> script28_gina_barlage(2*ones(4))
There are 16 even numbers

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