how can i convert hourly data for a year to daily data?

3 次查看（过去 30 天）
ABDULLA RAHIL
ABDULLA RAHIL 2015-6-3
回答： Albatross 2015-6-12
my data start from 1:1:8760 how can i chnge it to daily data with 365 data instead of 8760
  1 个评论
Ingrid
Ingrid 2015-6-3
depends on what you want to do? How do you want to make the conversion. Do you require daily average, daily maximum, daily minimum, value at noon each day, ....

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Salaheddin Hosseinzadeh
Hi Abdulla,
You may wanna have a look at reshape() function.
Put your data in a column, (apparently its a vector now)
data = data(:); this is one way to make a single column
Than you can reshape your column to a matrix of 360 X N if you like. However 8760 does not generate an integer if divided by 360, so I suggest you pad your data first of all with required number of zeros.
So finally you will have a 360xN data where N is the number of years (about 25 years of data). But keep in mind you will end up with a Matrix.
Hope this helps.
  3 个评论
显示 1更早的评论
Salaheddin Hosseinzadeh
Salaheddin Hosseinzadeh 2015-6-3
Abdulla,
I think I forgot that we've 365 days in a year! I confused with 2Pi or 360 degrees! lol
I need to practice the number of finger in one hand, number of days in a month and ... LOL
Anyhow, hope you're problem is solved now that you kindly accepted my answer.
Good luck
ABDULLA RAHIL
ABDULLA RAHIL 2015-6-12
many thanks for your answer but I am struggling to do that even I tried many times , i will send the file to you and see if it is possible or not

请先登录，再进行评论。

更多回答（1 个）

Albatross
Albatross 2015-6-12
I suspect you want to do something like this:
a=1:1:8760;
b=reshape(a,24,365)'

类别

在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by