Read binary file 3 bytes at a time

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Hi, I am new and I discovered that the fread by default reads a binary file 1 byte at a time, how can I read the file 3 bytes at a time. Thanks

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James Tursa
James Tursa 2015-6-10
编辑:James Tursa 2015-6-10
Try something like this. It reads in the entire file as uint8, groups them in 3 bytes, inserts an extra 0 byte in front of the group of 3, and then reinterprets the bytes as 4 byte unsigned integers. If you don't get the result you want, we may have endian issues to deal with and may need to swap bytes.
x = fread(fid,inf,'*uint8'); % read as uint8
x = reshape(x,3,[]); % groups of 3 in columns
[m,n] = size(x); % get size
x = [zeros(1,n,'uint8'); x]; % insert row of 0's at top to get 4 bytes per number
x = typecast(x(:),'uint32'); % reinterpret bytes as 4-byte unsigned integers
  4 个评论
Domenico Bellantoni
ahha ok, It was also my fault, I copied and pasted it without checking. Ok now it goes through but it stops at the last line with this error:
Error using typecast The first input argument must be a vector.
James Tursa
James Tursa 2015-6-10
Sorry, you grabbed it before my last edit using x(:) in the last line.

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更多回答(2 个)

Guillaume
Guillaume 2015-6-10
A much simpler solution would have been to read the file with a precision of 'ubit24' (or 'bit24' if the integer are signed), which is basically a 3 byte integer:
x = fread(fid, 'ubit24'); %that's it. all done
  1 个评论
James Tursa
James Tursa 2015-6-11
Good one ... I learned something today about formats available for fread.

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Walter Roberson
Walter Roberson 2015-6-10
  4 个评论
James Tursa
James Tursa 2015-6-10
编辑:James Tursa 2015-6-10
Do you mean you have a file of many bytes, and each group of 3 bytes in the file should be read in as an individual number? If so, what type of number? An integer of some sort?
Domenico Bellantoni
编辑:Domenico Bellantoni 2015-6-10
@James , yes! Just like that! They are unsigned integer.for each line of the file there is an integer number represented using 3 bytes and I want to read it

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