Converting 16-bit, little-endian, 2's complement integer to regular integer

Ben
2015 6 12
1 个回答
回答已采纳
更新时间：2015 6 14
9 次查看（30 天）

0 个投票

I'm trying to get various data sets (accelerometer, gyroscope etc.) from a AHRS (a CHR-UM6) and I'm having trouble getting the values out in the correct form. The data received (for each value) is a two row column vector such as:
247
255
These numbers are 16-bit, little-endian, 2's complement and I need to get the actual value. I hope someone can help!
Thanks, Ben

请先登录，再回答此问题。

 采纳的回答

Walter Roberson
Walter Roberson 2015-6-12

1 个投票

swapbytes(typecast(TheByteVector, 'int16'))
TheByteVector should be uint8.

2 个评论
显示 无 隐藏 无

Ben
Ben 2015-6-13
At first I didn't think this was going to work as swapbytes just seems to switch between little and big endian and I was worried about the two's complement part, but I was pleasantly surprised when my output values were what they should've been, thanks. My code is as follows, for reference:
gyro_x = double(swapbytes(typecast((uint8(packet.data(1:2))),'int16')))*0.0610352;
This is used multiple times for different values. The input packet.data is a double. If there's a cleaner/quicker/more efficient way to do what I'm doing, please share, thanks.
Walter Roberson
Walter Roberson 2015-6-14
gyro_x = double(typecast(uint8(packet.data([2 1]),'int16')) * 0.0610352;
No need to call swapbytes if you don't need to ;-)

请先登录，再进行评论。

更多回答（0 个）

类别

在 帮助中心 和 File Exchange 中查找有关 Inertial Sensor Fusion 的更多信息

产品

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by