Array/Data Strucutre Returns Problem

1 次查看（过去 30 天）
Dong-Kyeong
Dong-Kyeong 2011-11-27
I made a data structure as the following:
idols(1).groupname='2pm';
idols(1).nummembers = 6;
idols(1).gender = 'boys';
idols(1).debut = 2008;
idols(1).member(1).name = 'chansung';
idols(1).member(1).birthyear = 1990;
idols(1).member(1).height = 184;
idols(1).member(1).blood = 'B';
idols(1).member(2).name = 'junho';
idols(1).member(2).birthyear = 1990;
idols(1).member(2).height = 178;
idols(1).member(2).blood = 'A';
Then
name=idols(1).groupname
/////////////
The result is
name =
2pm
////////////
If I want the result to be the same as the input, i.e. name='2pm' How should I receive or change the value? Assuming that the method of making the data structure is not changed.
PS: It seems to be the case that if I make the data structure differently, it gives '2pm' instead of 2pm.

请先登录，再回答此问题。

采纳的回答

Junaid
Junaid 2011-11-27
I think you can't compare two string with == . You will get dimensions mismatch. As for string '2pm' the length = 3 and for 'SNSD' the length =4. You can use string compare function.
let say.
if (strcmp(idols(1).groupname, idols(2).groupname))
fprintf('Group is 2pm, or whatever you want');
end

更多回答（1 个）

Junaid
Junaid 2011-11-27
As I understand that
if you store
idols(1).groupname='2pm';
and when you type
idols(1).groupname
you get
2pm. But you are interested to get '2pm'. right ? If yes then it can be as simple as you store them with ' ' .
ex.
idols(1).groupname='''2pm''';
then if you type
idols(1).groupname
you will get
'2pm'
  3 个评论
显示 1更早的评论
Dong-Kyeong
Dong-Kyeong 2011-11-27
What I want to do is
function []=Func(idols,varargin)
if idols(1).groupname==varargin(1)
disp('Group is 2pm');
end
end
Func(idols,'2pm','SNSD')
Is it possible?
Walter Roberson
Walter Roberson 2011-11-27
No. You cannot compare strings or cell arrays using "==" . To compare strings you should use strcmp() or strcmpi().
if strcmpi(idols(1).groupname, varargin(1))

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Data Types 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by