How do you set a default reference for structure fields.

Question

Eric 2015-6-18

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编辑： Stephen23 2015-6-19

Suppose I have the structure "structure1" that has 3 fields a, b, c. I pass this structure to a function to perform some operations. I would like to setup the function as follows

function out = function(structure1)
% set structure 1 as the default field reference
?command? structure1
out = a + b*c;

I am trying to avoid

out = structure1.a + structure1.b*structure.c;

or

a = structure1.a;
b = structure1.b;
c = structure1.c;
out = a+b*c;

I seem to remember there was a command that did this in release 13 but I just cannot remember the command itself.

Thanks for your help,

Eric

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Azzi Abdelmalek 2015-6-18

What is your question?

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Answer 1

Tim 2015-6-18

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There's this one from the file exchange that does what you want:

v2struct

I think you would just do:

v2struct(structure1);

And it would pull a b and c as variables.

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Eric 2015-6-19

编辑：Eric 2015-6-19

Thanks, I will look into it.

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Answer 2

Stephen23 2015-6-18

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/224452-how-do-you-set-a-default-reference-for-structure-fields#answer_183232

编辑：Stephen23 2015-6-19

在 MATLAB Online 中打开

You could use struct2cell and deal to allocate those field values to separate variables, but this depends on the order in which the fields were defined:

>> S.a = 1;
>> S.b = 2;
>> S.c = 3;
>> C = struct2cell(S);
>> [a,b,c] = deal(C{:})
a =
     1
b =
     2
c =
     3

The most robust solution would be as you wrote in your question:

a = structure1.a;
b = structure1.b;
c = structure1.c;

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Eric 2015-6-19

Thank you. I will probably go with the second part sin alreadyce that is what I have already. The data structure I am dealing with is quite large and the work has been done already, I was just hoping to cut down on the number of lines and speed the script up.

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