How do you set a default reference for structure fields.

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Eric
Eric 2015-6-18
编辑： Stephen23 2015-6-19
Suppose I have the structure "structure1" that has 3 fields a, b, c. I pass this structure to a function to perform some operations. I would like to setup the function as follows
function out = function(structure1)
% set structure 1 as the default field reference
?command? structure1
out = a + b*c;
I am trying to avoid
out = structure1.a + structure1.b*structure.c;
or
a = structure1.a;
b = structure1.b;
c = structure1.c;
out = a+b*c;
I seem to remember there was a command that did this in release 13 but I just cannot remember the command itself.
Thanks for your help,
Eric

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采纳的回答

Tim
Tim 2015-6-18
There's this one from the file exchange that does what you want:
v2struct
I think you would just do:
v2struct(structure1);
And it would pull a b and c as variables.

更多回答（1 个）

Stephen23
Stephen23 2015-6-18
编辑：Stephen23 2015-6-19
You could use struct2cell and deal to allocate those field values to separate variables, but this depends on the order in which the fields were defined:
>> S.a = 1;
>> S.b = 2;
>> S.c = 3;
>> C = struct2cell(S);
>> [a,b,c] = deal(C{:})
a =
1
b =
2
c =
3
The most robust solution would be as you wrote in your question:
a = structure1.a;
b = structure1.b;
c = structure1.c;
  1 个评论
Eric
Eric 2015-6-19
Thank you. I will probably go with the second part sin alreadyce that is what I have already. The data structure I am dealing with is quite large and the work has been done already, I was just hoping to cut down on the number of lines and speed the script up.

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