How to replace a value in function

Hello, I automate the following function
f=@(x)0;
for i=1:3
h=@(x)x(i)^2
f=@(x) f(x) +h(x) % f= x(1)^2+x(2)^2+x(3)^2
end
The ISSUE IS:I want to replace x(3) =3 , so that the function would instead represent f=x(1)^2+x(2)^2+9. Is it possible?
Background information: My main goal is to to automatically create an abstract function (not necessarily the one mentioned above), replace it with known values of x and minimize it.
Any help whatsoever is hugely appreciated!
Thank you, Ela

回答(2 个)

Abandon all that complicated nonsense, and simply do this:
x = 1 : 3;
f = sum(x.^2)

1 个评论

The actual function i want to minimize is something like:
((((x(3)-x(1))^2 + (x(4)-x(2))^2 -25)/25)^2 +(((x(5)-x(1))^2 + (x(6)-x(2))^2 -9)/9)^2) +2*x(2)
I am able to generate the function. Although would appreciate a more optimal way.
The ISSUE is, I want to substitue x(4)=5, x(3) = 4 so that the function would look like ((((4-x(1))^2 + (5-x(2))^2 -25)/25)^2 +(((x(5)-x(1))^2 + (x(6)-x(2))^2 -9)/9)^2) +2*x(2)
and I can minimize the above.

请先登录,再进行评论。

f=@(x) x^2
som=0
for k=1:3
som=som+f(k)
end

2 个评论

Thanks for the response! I don't have problems creating the function, but rather replacing a variable in function.
For eg: I am able to create f(x) = x(1)^2+x(2)^2. Is there anyway to make the function f(x) = x(1)^2 + 4, and minimize it.
Thanks again!

请先登录,再进行评论。

类别

帮助中心File Exchange 中查找有关 Structures 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by