How to break down a text file
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I need to break down a text file into its respective columns. It has 6 columns. Would I format the code along the lines of something like this?
s271.1_hD = readCatalog(s27WHW02_LS220_j0_rx3_full_cc_fheat1.1_hD)
fid = fopen( 's27WHW02_LS220_j0_rx3_full_cc_fheat1.1_hD.txt');
data = textscan(fid, '%s', 'Delimiter', '\n', 'whitespace','');
fclose(fid);
list.time = data{1};
list.h+eq = data{2};
list.hxeq = data{3};
list.h+p = data{4};
list.hxp = data{5};
list.rho_c = data{6};
return
My file I need to break down is attached. Thank you!
1 个评论
per isakson
2015-6-21
编辑：per isakson
2015-6-21
I assume you want to convert to double. Try to replace
data = textscan(fid, '%s', 'Delimiter', '\n', 'whitespace','');
by
data = textscan( fid, '%f%f%f%f%f%f' );
采纳的回答
Azzi Abdelmalek
2015-6-21
编辑：Azzi Abdelmalek
2015-6-21
You can use dlmread function
M=dlmread('s27WHW02_LS220_j0_rx3_full_cc_fheat1.1_hD.txt')
list=cell2struct(num2cell(M),{'f1' ,'f2','f3','f4','f5' ,'f6'},2)
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