Increasing size of Multidimensional Array

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teresa
teresa 2015-6-22
评论： Guillaume 2015-6-22
Hi all,
I have one multidimensional array T of size (n1,n2,n3,...) and I need to build a new array S of size (n1+1,n2+1,n3+1,...) with the same values of A and zeros in all the added coefficients. In other words, I need to pad one "slice" of zeros at the end of each dimension of T.
The problem is that I don't know the size of T until runtime... so code should work for any number of dimensions...
Any idea how to do it? (other than a extremely slow loop in all coefficients of A) Thanks in advance! Sergio
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Azzi Abdelmalek
Azzi Abdelmalek 2015-6-22
Usuaris, have you looked at the two answers?
teresa
teresa 2015-6-22
I haven't! sorry.
Your solution is more simple than mine. Thanks for your answer.

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回答（2 个）

Azzi Abdelmalek
Azzi Abdelmalek 2015-6-22
idx=num2cell(size(T)+1);
T(idx{:})=0;
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Stephen23
Stephen23 2015-6-22
编辑：Stephen23 2015-6-22
Very tidy solution. To answer the original question first assign T to a new array S:
S = T;
X = num2cell(1+size(S));
S(X{:}) = 0;
Guillaume
Guillaume 2015-6-22
Indeed! Much simpler (and faster) than mine.

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Guillaume
Guillaume 2015-6-22
newT = zeros(size(T) + 1); %create new array with increased size
destidx = arrayfun(@(s) 1:s, size(T), 'UniformOutput', false);
newT(destidx{:}) = T
The last line is the programmatic equivalent of
newT(1:size(T, 1), 1:size(T, 2), 1:size(T, 3), ...) = T
And the line before that is just building these indices

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