Increasing size of Multidimensional Array
显示 更早的评论
Hi all,
I have one multidimensional array T of size (n1,n2,n3,...) and I need to build a new array S of size (n1+1,n2+1,n3+1,...) with the same values of A and zeros in all the added coefficients. In other words, I need to pad one "slice" of zeros at the end of each dimension of T.
The problem is that I don't know the size of T until runtime... so code should work for any number of dimensions...
Any idea how to do it? (other than a extremely slow loop in all coefficients of A) Thanks in advance! Sergio
3 个评论
teresa
2015-6-22
Azzi Abdelmalek
2015-6-22
Usuaris, have you looked at the two answers?
teresa
2015-6-22
回答（2 个）
Azzi Abdelmalek
2015-6-22
idx=num2cell(size(T)+1);
T(idx{:})=0;
2 个评论
Very tidy solution. To answer the original question first assign T to a new array S:
S = T;
X = num2cell(1+size(S));
S(X{:}) = 0;
Guillaume
2015-6-22
Indeed! Much simpler (and faster) than mine.
Guillaume
2015-6-22
newT = zeros(size(T) + 1); %create new array with increased size
destidx = arrayfun(@(s) 1:s, size(T), 'UniformOutput', false);
newT(destidx{:}) = T
The last line is the programmatic equivalent of
newT(1:size(T, 1), 1:size(T, 2), 1:size(T, 3), ...) = T
And the line before that is just building these indices
类别
在 帮助中心 和 File Exchange 中查找有关 Resizing and Reshaping Matrices 的更多信息
产品
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
