remove the NaN numbers from a matrix without loop
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Hello Matlab Users,
In my matrix of NxD dimension, I know that the number of NaNs on each row are the same, however the position of these NaN elements differ between rows. Is there an efficient way to remove NaN's from this matrix while keeping the shape of matrix, as shown in the simplified example:
A=[ 1 2 3 NaN 4 5 NaN; 6 NaN 7 8 NaN 9 10]
and I would like to be able to remove NaNs and get:
A_mod=[ 1 2 3 4 5; 6 7 8 9 10]
I appreciate your help, NF
采纳的回答
Walter Roberson
2011-11-28
At = A.';
A_mod = reshape(At(~isnan(At)),[],size(A,1)).';
更多回答（1 个）
bym
2011-11-28
A_mod = A(~isnan(A)); %untested
3 个评论
Walter Roberson
2011-11-28
No, that will not maintain the number of rows, and does not get the elements in the right position to be reshape()'d in to rows.
bym
2011-11-28
right
Noushin Farnoud
2011-11-29
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2011-11-28
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