Find index in each column of a matrix using for
3 次查看(过去 30 天)
显示 更早的评论
Good evening,
I am attempting to find the index of the last non-NaN for each column in a matrix. I can't really get it to work correctly; instead of giving me a column vector of indices, it sums the indices together in every cell. Here is my code:
xDate=zeros(1,size(forward,2)); % preallocate a vector
xDate=xDate'; % transpose to a column
for i = 1:size(forward,2)
xDate(i) = find(~isnan(forward),1,'last')
end
I'm sure it is an easy fix; but I've been racking my brain on it for hours now with no solution.
Thanks to all who are generous enough to help.
0 个评论
采纳的回答
Star Strider
2015-6-28
I don’t have your ‘forward’ matrix so this is just a guess.
See if indexing ‘forward’ as well works:
xDate(i) = find(~isnan(forward(:,i)),1,'last')
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!